
c
F(x) = 2(x+1)3 – 6(x+1)
= (2x +2)3 – (6x – 6)
= 6x + 6 – 6x – 6
= 0
= (2x +2)3 – (6x – 6)
= 6x + 6 – 6x – 6
= 0
f(x) = g(x) —–> kita misalkan nilainya adlah 2
f(x) = 3.2 -6
= 0
g(x) = 2.2 + a
0 = 4 + (-4)
yg no 2 aq bgung…
f